Flex Recruitment Drive 2022: Flex is hiring freshers with engineering graduates for Junior Engineer in the Pune location. Following are the Flex Recruitment Drive 2022 process and details.
Company Name: Flex
Job Role: Junior Engineer
Location: Pune
Experience: Fresher
Education: B.E/B.Tech
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Flex Recruitment Drive 2022
Candidates with B.E/B.Tech is eligible for applying for Flex careers. Below are the Flex Recruitment Drive description and eligibility criteria.
Job Description:
- Creates, implements, and finalizes engineering change orders (ECO’s) and makes system changes.
- Performs file maintenance of BOMs, parts drawings, ECO’s, process alerts, and other customer documents.
- Coordinates ECO status with customers and implements cost changes and effective dates.
- Ensures projects are in compliance with document control policies and procedures.
- Ensures data accuracy and completeness of documentation including logs, reports, and distribution.
- Manages and tracks product configuration and manufacturing/customer requirements.
- Responsible for the interface between program manager, engineering, manufacturing, and materials to ensure appropriate changes are documented.
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Eligibility Criteria and Skills:
- Minimum 0- 2 years of experience in a manufacturing setup, preferably in the EMS industry
- B.E Electronics and Communication Engineering / EEE / Mechanical / Electronics
- Knowledge of MS Office and MS outlook
- Sound Knowledge on a technical subject.
- Good written and oral communication skills
- Very Good analytical and logical reasoning skills
- Good Attitude
- Ready to work in night shifts
Flex Freshers Salary:
- Salary not mentioned(As per Industry)
- Flex Pune will be the work location
How to Apply for Flex Recruitment Drive 2022?
All eligible and interested candidates can apply for Flex careers using the below-provided link. Fill up all the details and further interview dates and details will be shared.
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